25 Feb
2012
25 Feb
'12
2:30 a.m.
On Fri, Feb 24, 2012 at 10:12:14PM -0800, Geoff Joy wrote:
If this were implemented across eight bits instead of
six the number
of subnets quadruples.
Good scheme!
I think we can take it as read that the /16s really are /16s
as the table says, not /18s as I once thought they'd have to
be, so you do have all 8 bits of the third octet to use.
I wonder if it might be wise to reserve the zero'th subnet?
- Brian